Silent Hill
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The first is larger than the second,
The second twice the third,
The third smaller than the fourth,
The fourth is half the first.
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Four of the number are not repeated,
Three are not in the top row,
Two are not in the right row,
One of the number is the final key.
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| 1 2 3 |
| 4 5 6 |
| 7 8 9 |
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* This was the password lock...
P/s Don't event ask me about the question, because i'm still stuck within and i'm not the author of this puzzle. I just can't pass throw the door which is lock in "Silent Hill"...lol
* If you have any clue, hope that you can help me solve it anyway...And of course show your solution why you said is that number. Please and please don't just paste some answer with no reason...
* Although i know that i can search through google for the password, but i still need to know how to solve this
....Another thing is my journal does not seem too bored for a view * May be there's alot of people can answer this, as far as i play "Silent hill" is easy to play....... I was so dumb with these kind of puzzle and IQ question, should i list in heavy left brain DUDE?!(With no detetive brain at all...) lol
Devious Comments
Let's see...
"Four of the number are not repeated" - means all the numbers are different.
"Three are not in the top row" - only one of the numbers is either 1 2 or 3
"Two are not in the right row" - two are NOT, which means two ARE the numbers; 3 6 or 9
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"The first is larger than the second
The second twice the third
The third smaller than the fourth
The fourth is half the first"
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You could assume that, because the clues are about being "twice" and "half" of certain numbers, that there are few, or even no odd numbers in the code: ruling out 5, 7 and 9.
If you did this, then it would mean 3 & 6 are definitely there. It would also rule out 1 and 2 because "three are not in the top row" and 3 is the only number from the top row.
This just leaves; 3, 4, 6, 8
From this, it would just be playing around with the numbers and seeing how they work out with the clues.
Hope that wasn't *too* confusing, Lol! And hope it helps
The second twice the third
The third smaller than the fourth
The fourth is half the first
I came up with 8, 6, 3, 4 in that order. I'm not sure what "one of the numbers is the final key" means, i thought maybe that meant one of the numbers was 9, but i couldnt find any way to make 9 work, since 9 is the largest number there, and cannot be divided or multiplied by two to get another number under 10, which is required of each number's position.
Hard to explain exactly how to figure this out, but maybe i can point out which numbers correspond to which rule....let's see. Only one number is in the top row, so the three, two numbers from the right row, 3 and 6, the first number has to be largest number of the combination and divisible by two, leaving 8, the third number has to be the smallest number, 3, the second needs be be smaller than the first, but multiplied by two, and the last number has two be half the first, leaving 4. I know that's a horrible confusing explanation, i confused myself O_o but give 8634 a shot, and see if it works
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~ Hiram Hibbard ~
But given you need 2 pairs of numbers (X, 2X) and (Y, 2Y) because you have 2 which are twice the other 2, you can assume the following pairs:
A = (1, 2)
B = (2, 4)
C = (3, 6)
D = (4, 8)
And that leaves out 5, 7 and 9.
A is ruled out by itself because of "Three are not in the top row".
B only allows another pair, which is C, but then the same verse applies.
That leaves you with pairs C and D.
Now have fun with them!
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